We know that perpendicular drawn from center bisect the chord. Let O is the center of given circle and radius is 13 cm, chord AB = 10 cm If radius of circle is 13 cm, () and length of its one chord is 10 cm, then find the length of the chord from the center. RBSE Solutions For Class 10 Maths Chapter 12.2 Question 2. (v) False, because a circle cannot be drawn though three collinear points. (iv) True, because chords of congruent circles, subtend equal angle at the center. (iii) True, because equal chords are equidistant from the center. (ii) False, because larger chords are closer from the center. (i) False, because longer chord subtends larger angle at the center, where as shorter chord subtends smaller angle at the center. (vi) A circle of 4 cm radius, passing through two points A and B can be drawn of AB = 8 cm. (v) A circle can be drawn from three collinear points. (iv) Two congruent circles having centers O and O’ intersect each other at two points A and B, then ∠AOB = ∠AO’B. (iii) If two chords AB and CD of a circle are at same distance 4 cm from center then AB = CD.
(ii) Two chords of length 10 cm and 8 cm are at a distance from center 8 cm and 5 cm respectively. Angles subtended by these chords at center are respectively 70° and 50°. (i) AB = 3 cm and CD = 4 cm are two chords of a circle. In the following, write () true/false and if possible give reason for your answer. Rajasthan Board RBSE Class 10 Maths Chapter 12 Circle Ex 12.2 RBSE Solutions for Class 10 Maths Chapter 12 Circle Ex 12.2 is part of RBSE Solutions for Class 10 Maths. Here we have given Rajasthan Board RBSE Class 10 Maths Chapter 12 Circle Exercise 12.2.
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